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[saag] for your comments Internet draft



I dont know how this works, but could this be included in your next agenda?
I need your inputs and comments,

http://tools.ietf.org/html/draft-d-sec-udt-00


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Sent: Wednesday, October 21, 2009 6:00 AM
Subject: saag Digest, Vol 16, Issue 4


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Today's Topics:

  1. Re: A question about AES properties... (bcn at ISI.EDU)


----------------------------------------------------------------------

Message: 1
Date: Mon, 19 Oct 2009 13:49:37 -0700
From: bcn at ISI.EDU
Subject: Re: [saag] A question about AES properties...
To: Ken Raeburn <raeburn at MIT.EDU>
Cc: John Border <John.Border at hughes.com>, "saag at ietf.org"
<saag at ietf.org>
Message-ID: <1255985377.4adcd0e19f8af at webmail.isi.edu>
Content-Type: text/plain; charset=ISO-8859-1

Quoting Ken Raeburn <raeburn at MIT.EDU>:

On Oct 15, 2009, at 15:56, John Border wrote:
>     I have what I thought was a simple question about the properties
> of AES.  But, I have not been able to find an answer.  Possibly that
> means the question itself is flawed (but I haven?t been able to
> figure that out either)?
>
>    With AES, does the order of the functions matter, i.e. does
> EK(DK(P)) = DK(EK(P))?


As Ken responded, if the plaintext is a multiple of the block size, because EK and DK are inverses, the result is the identity function, so the answer to the
above is that the order does not make a difference.

BUT, I expect what you might have been trying to ask is whether EK1(DK2(P)) = DK2(EK1(P)), i.e. your question above, but using two different keys. In this case, the analyses is not as simple, and I would guess that the answer is that no they are not the same. But I could be wrong. You should be able to verify
the "NO" answer with a simple experiment.

Clifford Neuman


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