# Line slope calculator 3x+4y=26

**Straight line given by points A[2; 5] and B[6; 2]**

## Calculation:

**Slope-intercept form of line:**y = -0.75x+6.5

**Canonical form of the line equation:**3x+4y-26 = 0

**Parametric form of the line equation:**

x = 4t+2

y = -3t+5 ; t ∈ R

**Slope:**m = -0.75

**Slope angle of line: φ =**-36°52'12″ = -0.6435 rad

**X intercept:**x

_{0}= 8.6667

**Y intercept:**y

_{0}= q = 6.5

**Distance line from the origin:**d

_{0}= 5.2

**The length of the segment AB: |AB| =**5

**Vector: AB =**(4; -3)

**Normal vector: n =**(3; 4)

**Midpoint of the segment AB: M =**[4; 3.5]

**Perpendicular Bisector equation:**4x-3y-5.5 = 0

**Vector OA = (2; 5) ; |OA| = 5.3852**

**Vector OB = (6; 2) ; |OB| = 6.3246**

**Scalar product OA .OB = 22**

**Angle ∠ AOB = 49°45'49″ = 0.8685 rad**